E
h
(Xi+1 − Xi) · 1{τ≥i+1}
i
= E
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
E
h
(Xi+1 − Xi) · 1{τ≥i+1}
i
= E
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.