Math Problem Solver

\[ \frac{1}{16} + \frac{1}{32} = \frac{3}{32} = 0.09375 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{16}\) and \(\frac{1}{32}\) is \(32\). \[ \begin{aligned} \frac{1}{16} + \frac{1}{32} &= \frac{1 \cdot 2}{16 \cdot 2} + \frac{1 \cdot 1}{32 \cdot 1} \\ &= \frac{2 + 1}{32} \\ &= \frac{3}{32} \end{aligned} \]