1480⋅0.95b0.95^{b}0.95b<480
asked by guest on Nov 27, 2024 at 11:33 am
You asked:
MathBot Answer:
b>log((1237)1log(1920))b > \log{\left(\left(\frac{12}{37}\right)^{\frac{1}{\log{\left(\frac{19}{20} \right)}}} \right)}b>log((3712)log(2019)1)