1-(1+ \dfrac{ .06 }{ 2 } ) ^ { -2 \times 5 }

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on Nov 28, 2024 at 1:21 am



You asked:

Evaluate the expression: 1−(1+.062)−2⋅51 - {\left( 1 + \frac{.06}{2} \right)}^{-2 \cdot 5}

MathBot Answer:

1−(1+.062)−2⋅5=34391637934412192049134391637934412192049≈0.255906085103274886881324084180991 - {\left( 1 + \frac{.06}{2} \right)}^{-2 \cdot 5} = \frac{34391637934412192049}{134391637934412192049} \approx 0.25590608510327488688132408418099

1−(1+.062)−2⋅5=1−(1+3502)−2⋅5=1−(1+3100)−2⋅5=1−(103100)−2⋅5=1−(103100)−10=1−100000000000000000000134391637934412192049=34391637934412192049134391637934412192049\begin{aligned}1 - {\left( 1 + \frac{.06}{2} \right)}^{-2 \cdot 5}&=1 - {\left( 1 + \frac{\frac{3}{50}}{2} \right)}^{-2 \cdot 5}\\&=1 - {\left( 1 + \frac{3}{100} \right)}^{-2 \cdot 5}\\&=1 - {\left( \frac{103}{100} \right)}^{-2 \cdot 5}\\&=1 - {\left( \frac{103}{100} \right)}^{-10}\\&=1 - \frac{100000000000000000000}{134391637934412192049}\\&=\frac{34391637934412192049}{134391637934412192049}\end{aligned}

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