3+sec^2(30)-cot^2(45)

asked by guest
on Mar 26, 2025 at 6:58 pm



You asked:

Evaluate the expression: 3+sec⁡(30)2−cot⁡(45)23 + {\sec\left( 30 \right)}^{2} - {\cot\left( 45 \right)}^{2}

MathBot Answer:

3+sec⁡(30)2−cot⁡(45)2=−cot⁡2(45)+3+sec⁡2(30)≈44.64712248635936300797103217207173 + {\sec\left( 30 \right)}^{2} - {\cot\left( 45 \right)}^{2} = - \cot^{2}{\left(45 \right)} + 3 + \sec^{2}{\left(30 \right)} \approx 44.6471224863593630079710321720717

3+sec⁡(30)2−cot⁡(45)2=3+sec⁡2(30)−cot⁡2(45)=(3+sec⁡2(30))−cot⁡2(45)=3+sec⁡2(30)−cot⁡2(45)\begin{aligned}3 + {\sec\left( 30 \right)}^{2} - {\cot\left( 45 \right)}^{2}&=3 + \sec^{2}{\left(30 \right)} - \cot^{2}{\left(45 \right)}\\&=\left(3 + \sec^{2}{\left(30 \right)}\right) - \cot^{2}{\left(45 \right)}\\&=3 + \sec^{2}{\left(30 \right)} - \cot^{2}{\left(45 \right)}\end{aligned}

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