10=80e^-0.5^x
You asked:
Investigate the equation: \(10 = 80 \cdot {e}^{-{0.5}^{x}}\).
MathBot Answer:
The solution is: \[x = - \frac{\log{\left(\log{\left(8 \right)} \right)}}{\log{\left(2 \right)}} \approx -1.0561961\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).