Could you calculate the value of the following expression?

∑t=1∞1(1+x)t\sum_{t=1}^{\infty}{\frac{1}{(1+x)^t}}

asked by guest
on Nov 16, 2024 at 3:04 pm



You asked:

Evaluate the expression: ∑t=1∞1(1+x)t\sum_{t = 1}^{\infty} {\frac{1}{{\left( 1 + x \right)}^{t}}}

MathBot Answer:

Simplified: ∑t=1∞1(1+x)t=∑t=1∞(x+1)−t\sum_{t = 1}^{\infty} {\frac{1}{{\left( 1 + x \right)}^{t}}} = \sum_{t=1}^{\infty} \left(x + 1\right)^{- t}

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