Determine the center and radius: x² + y² + 14x - 2y = -1
You asked:
Find the center and the radius of \({x}^{2} + {y}^{2} + 14 x - 2 y = -1\)
MathBot Answer:
The center of the circle \(x^{2} + 14 x + y^{2} - 2 y = -1\) is at \(\left( -7, \ 1\right)\).
The radius of the circle \(x^{2} + 14 x + y^{2} - 2 y = -1\) is \(7\).