Math Problem Solver

\[ 8\frac{2}{6} + 1\frac{10}{2} = \frac{43}{3} = 14.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{8}{1}\), \(\frac{2}{6}\), \(\frac{1}{1}\), and \(\frac{10}{2}\) is \(6\). \[ \begin{aligned} 8\frac{2}{6} + 1\frac{10}{2} &= \frac{8 \cdot 6}{1 \cdot 6} + \frac{2 \cdot 1}{6 \cdot 1} + \frac{1 \cdot 6}{1 \cdot 6} + \frac{10 \cdot 3}{2 \cdot 3} \\ &= \frac{48 + 2 + 6 + 30}{6} \\ &= \frac{86}{6} \\&= \frac{43}{3} \end{aligned} \]