limx→π (sin x)/(x – π) is equal to

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on Nov 26, 2024 at 6:21 am



You asked:

Evaluate the expression: lim⁡x→πsin⁡(x)x−π\lim_{x \to π}{\frac{\sin\left( x \right)}{x - \pi}}

MathBot Answer:

lim⁡x→πsin⁡(x)x−π=sin⁡(π)π−π\lim_{x \to π}{\frac{\sin\left( x \right)}{x - \pi}} = \frac{\sin{\left(π \right)}}{π - \pi}
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