factor: 64r^3-27
You asked:
Factor the expression: \(\displaystyle 64 \cdot {r}^{3} - 27\)
MathBot Answer:
Factorization over the rational numbers:
\[\left(4 r - 3\right) \left(16 r^{2} + 12 r + 9\right)\]Factorization over the complex numbers:
\[64 \left(r - \frac{3}{4}\right) \left(r + \left(\frac{3}{8} - \frac{3 \sqrt{3} i}{8}\right)\right) \left(r + \left(\frac{3}{8} + \frac{3 \sqrt{3} i}{8}\right)\right)\]\(i\) is the imaginary unit, defined as \(i^2 = -1\).