$$\int(x^3+ 9x^2+48x+2\) dx$$

asked by guest
on Oct 18, 2024 at 11:30 pm



You asked:

Evaluate the integral: \(\int{{x}^{3} + 9 \cdot {x}^{2} + 48 x + 2}dx\)

MathBot Answer:

Antiderivative

\[\int{{x}^{3} + 9 \cdot {x}^{2} + 48 x + 2}dx = 2 x + 3 x^{3} + 24 x^{2} + \frac{x^{4}}{4} + C\]