2xy √81n^9/3x^3* y^12
asked by guest on Apr 07, 2025 at 9:54 am
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MathBot Answer:
2xy81⋅n93x3y12=6n9y13x2\frac{2 x y \sqrt{81} \cdot {n}^{9}}{3 {x}^{3}} {y}^{12} = \frac{6 n^{9} y^{13}}{x^{2}}3x32xy81⋅n9y12=x26n9y13