$\sqrt{5}$ = $\sqrt{y^2-10y+26}$

asked by guest
on Sep 19, 2024 at 9:07 pm



You asked:

Solve the equation \(\sqrt{5} = \sqrt{{y}^{2} - 10 y + 26}\) for the variable \(y\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}y &= 3\\y &= 7\end{aligned}\]

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