Math Problem Solver

\(2487\) rounded to the nearest \(10\) is \(2490\).

Rounding \(2487\) to the nearest \(10\) is equivalent to finding the integer multiple of \(10\) nearest to \(2487\).

The two consecutive multiples of \(10\) that \(2487\) falls between are:\[248 \cdot 10 = 2480\] and \[(248 + 1) \cdot 10 = 2490\] So:\[2480 \le 2487 \le 2490\]

The distance from \(2487\) to \(2480\) is \(\left| 2487 - 2480 \right| = 7\).

The distance from \(2487\) to \(2490\) is \(\left| 2487 - 2490 \right| = 3\).

\(2487\) is closer to \(2490\) than it is to \(2480\), so \(2487\) rounded to the nearest \(10\) is \(2490\).

\(248\) from the above statement about consecutive multiples of \(10\) can be computed from the formula for the greatest integer \(n\) such that \(n \cdot 10 \le 2487\): \[ n = \operatorname{floor}\left(2487 \div 10 \right) = \operatorname{floor}\left(248.7 \right) = 248\]