4.225 (RC) + RC = 80

asked by guest
on Nov 24, 2024 at 4:02 am



You asked:

Investigate the equation: \(4.225 \cdot R C + R C = 80\).

MathBot Answer:

The graph of the equation \(4.225 \cdot R C + R C = 80\) is a hyperbola.

The coordinates of its foci are: \(\left(- \frac{80 \sqrt{209}}{209}, - \frac{80 \sqrt{209}}{209}\right)\) and \(\left(\frac{80 \sqrt{209}}{209}, \frac{80 \sqrt{209}}{209}\right)\).

The coordinates of its vertices are: \(\left(- \frac{40 \sqrt{418}}{209}, - \frac{40 \sqrt{418}}{209}\right)\) and \(\left(\frac{40 \sqrt{418}}{209}, \frac{40 \sqrt{418}}{209}\right)\).

The asymptotes have equations: \(- 160 \sqrt{418} C = 0\) and \(- 160 \sqrt{418} R = 0\).

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