Math Problem Solver

\[ \frac{1}{12} + \frac{1}{4} = \frac{1}{3} = 0.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{12}\) and \(\frac{1}{4}\) is \(12\). \[ \begin{aligned} \frac{1}{12} + \frac{1}{4} &= \frac{1 \cdot 1}{12 \cdot 1} + \frac{1 \cdot 3}{4 \cdot 3} \\ &= \frac{1 + 3}{12} \\ &= \frac{4}{12} \\&= \frac{1}{3} \end{aligned} \]