3y^3 − 2y^2 + 1

asked by guest
on Apr 07, 2025 at 7:38 am



You asked:

Evaluate the expression: 3y3−2y2+13 {y}^{3} - 2 {y}^{2} + 1

MathBot Answer:

3y3−2y2+1=3y3−2y2+13 {y}^{3} - 2 {y}^{2} + 1 = 3 y^{3} - 2 y^{2} + 1

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