Math Problem Solver

\[ 3\frac{2}{3} + 2\frac{2}{3} = \frac{19}{3} = 6.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{2}{3}\), \(\frac{2}{1}\), and \(\frac{2}{3}\) is \(3\). \[ \begin{aligned} 3\frac{2}{3} + 2\frac{2}{3} &= \frac{3 \cdot 3}{1 \cdot 3} + \frac{2 \cdot 1}{3 \cdot 1} + \frac{2 \cdot 3}{1 \cdot 3} + \frac{2 \cdot 1}{3 \cdot 1} \\ &= \frac{9 + 2 + 6 + 2}{3} \\ &= \frac{19}{3} \end{aligned} \]