2781.711004*(cos(10)+(0.0473/0.14974)*cos(2*10)-(1/4)*((0.0473/0.14974)^3)*cos(4*10))
asked by guest
on Mar 17, 2025 at 2:34 am
You asked:
Evaluate the expression:
2781.711004(cos(10)+0.149740.0473cos(2⋅10)−41(0.149740.0473)3cos(4⋅10))
MathBot Answer:
2781.711004(cos(10)+0.149740.0473cos(2⋅10)−41(0.149740.0473)3cos(4⋅10))=250000695427751cos(10)−335748040242400073592819058545567cos(40)+374350000328937326223cos(20)≈−1960.85852244492223770716638870508527
2781.711004(cos(10)+0.149740.0473cos(2⋅10)−41(0.149740.0473)3cos(4⋅10))=(2781+1000000711004)⋅(cos(10)+10000473⋅100000149741⋅cos(2⋅10)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=(2781+250000177751)⋅(cos(10)+10000473⋅100000149741⋅cos(2⋅10)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+10000473⋅100000149741⋅cos(2⋅10)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+10000473⋅5000074871⋅cos(2⋅10)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+10000473⋅748750000⋅cos(2⋅10)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+10000473⋅748750000⋅cos(20)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅(10000473⋅100000149741)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅(10000473⋅5000074871)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅(473⋅74875)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅(74872365)3⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅41968505030313227977125⋅cos(4⋅10))=250000695427751⋅(cos(10)+74872365⋅cos(20)−41⋅41968505030313227977125⋅cos(40))=250000695427751⋅(cos(10)+74872365⋅cos(20)−167874020121213227977125⋅cos(40))=250000695427751⋅((74872365⋅cos(20)+cos(10))−167874020121213227977125⋅cos(40))=250000695427751⋅(−167874020121213227977125⋅cos(40)+74872365⋅cos(20)+cos(10))=−335748040242400073592819058545567⋅cos(40)+250000695427751⋅cos(10)+374350000328937326223⋅cos(20)