2x³y+3xz² if x=2 y=3 and z=4
asked by guest on Nov 16, 2024 at 8:45 am
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MathBot Answer:
2x3y+3xz2=1442 {x}^{3} y + 3 x {z}^{2} = 1442x3y+3xz2=144
2x3y+3z2x=2⋅3⋅23+3⋅42⋅2=3⋅42⋅2+2⋅3⋅8=2⋅3⋅8+3⋅16⋅2=3⋅16⋅2+48=48+96=144\begin{aligned}2 x^{3} y + 3 z^{2} x&=2 \cdot 3 \cdot 2^{3} + 3 \cdot 4^{2} \cdot 2\\&=3 \cdot 4^{2} \cdot 2 + 2 \cdot 3 \cdot 8\\&=2 \cdot 3 \cdot 8 + 3 \cdot 16 \cdot 2\\&=3 \cdot 16 \cdot 2 + 48\\&=48 + 96\\&=144\end{aligned}2x3y+3z2x=2⋅3⋅23+3⋅42⋅2=3⋅42⋅2+2⋅3⋅8=2⋅3⋅8+3⋅16⋅2=3⋅16⋅2+48=48+96=144
