x⁸+ x³
asked by guest on Mar 29, 2025 at 7:44 pm
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MathBot Answer:
x8+x3=x8+x3\displaystyle {x}^{8} + {x}^{3} = x^{8} + x^{3} x8+x3=x8+x3
x8+x3=x3(x+1)(x4−x3+x2−x+1){x}^{8} + {x}^{3} = x^{3} \left(x + 1\right) \left(x^{4} - x^{3} + x^{2} - x + 1\right)x8+x3=x3(x+1)(x4−x3+x2−x+1)