(x+3)^2/8 + (y-4)^2/8 = 1
You asked:
Investigate the equation: \(\frac{{\left( x + 3 \right)}^{2}}{8} + \frac{{\left( y - 4 \right)}^{2}}{8} = 1\).
MathBot Answer:
The graph of the equation \(\frac{{\left( x + 3 \right)}^{2}}{8} + \frac{{\left( y - 4 \right)}^{2}}{8} = 1\) is a circle.
The coordinates of its center are \(\left(-3, 4\right)\).
Its radius is \(2 \sqrt{2}\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= -3 + 2 \sqrt{2} \cos{\left(\theta \right)}\\y\left(\theta\right) &= 4 + 2 \sqrt{2} \sin{\left(\theta \right)}\end{aligned}\]