f(-0.49)=x^5-5x^4+5x^3+x^2+3x+2

asked by guest
on Dec 27, 2024 at 3:54 pm



You asked:

Investigate the relation \(f\left( -0.49 \right) = {x}^{5} - 5 {x}^{4} + 5 {x}^{3} + {x}^{2} + 3 x + 2\).

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