limx→e+
(lnx)^
1/
(x−e)
You asked:
Evaluate the expression: \(\lim_{x \to e^+}{\frac{{\ln\left( x \right)}^{1}}{x - e}}\)
MathBot Answer:
\[\lim_{x \to e^+}{\frac{{\ln\left( x \right)}^{1}}{x - e}} = \infty\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).