(x-2)(x-3)(x-5)
asked by guest on Apr 04, 2025 at 9:05 pm
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MathBot Answer:
(x−2)(x−3)(x−5)=(x−5)(x−3)(x−2)\displaystyle \left(x - 2\right) \left(x - 3\right) \left(x - 5\right) = \left(x - 5\right) \left(x - 3\right) \left(x - 2\right) (x−2)(x−3)(x−5)=(x−5)(x−3)(x−2)
(x−2)(x−3)(x−5)=x3−10x2+31x−30\left(x - 2\right) \left(x - 3\right) \left(x - 5\right) = x^{3} - 10 x^{2} + 31 x - 30(x−2)(x−3)(x−5)=x3−10x2+31x−30