$$(x^3+3x^2-6x-6)*(-x^3+3x^2-8x-6)$$

asked by guest
on May 05, 2024 at 3:04 pm

You asked:

Evaluate the expression: \(\left({x}^{3} + 3 \cdot {x}^{2} - 6 x - 6\right) \cdot \left(-{x}^{3} + 3 \cdot {x}^{2} - 8 x - 6\right)\)

MathBot Answer:

Evaluated



\(\displaystyle \left({x}^{3} + 3 \cdot {x}^{2} - 6 x - 6\right) \cdot \left(-{x}^{3} + 3 \cdot {x}^{2} - 8 x - 6\right) = \left(- x^{3} + 3 x^{2} - 8 x - 6\right) \left(x^{3} + 3 x^{2} - 6 x - 6\right) \)

Expanded

\[\left({x}^{3} + 3 \cdot {x}^{2} - 6 x - 6\right) \cdot \left(-{x}^{3} + 3 \cdot {x}^{2} - 8 x - 6\right) = - x^{6} + 7 x^{4} - 42 x^{3} + 12 x^{2} + 84 x + 36\]

Factored

\[\left({x}^{3} + 3 \cdot {x}^{2} - 6 x - 6\right) \cdot \left(-{x}^{3} + 3 \cdot {x}^{2} - 8 x - 6\right) = - \left(x^{3} - 3 x^{2} + 8 x + 6\right) \left(x^{3} + 3 x^{2} - 6 x - 6\right)\]

asked 13 days ago

active 13 days ago