2+x=2×10−1\sqrt{2}+x=\sqrt{2}\times 10^{-1}

asked by stcoffice19
on Mar 25, 2025 at 4:17 am



You asked:

Solve the equation 2+x=2⋅10−1\sqrt{2} + x = \sqrt{2} \cdot {10}^{-1} for the variable xx.

MathBot Answer:

The solution is: x=−9210≈−1.2727922x = - \frac{9 \sqrt{2}}{10} \approx -1.2727922

x+2=210x=−9210\begin{aligned}x + \sqrt{2} &= \frac{\sqrt{2}}{10}\\x &= - \frac{9 \sqrt{2}}{10}\end{aligned}

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