6y^5-8y^3-2y+1=0

find y

asked by guest
on Nov 24, 2024 at 5:47 am



You asked:

Solve the equation 6y5−8y3−2y+1=06 {y}^{5} - 8 {y}^{3} - 2 y + 1 = 0 for the unknown yy.

MathBot Answer:

The 5 solutions to the equation are: y≈−1.2727678y≈0.34743302y≈1.211102y=−0.142883587651334−0.539249614351203i≈−0.14288359−0.53924961iy=−0.142883587651334+0.539249614351203i≈−0.14288359+0.53924961i\begin{aligned}y &\approx -1.2727678\\y &\approx 0.34743302\\y &\approx 1.211102\\y &= -0.142883587651334 - 0.539249614351203 i \approx -0.14288359 -0.53924961 i\\y &= -0.142883587651334 + 0.539249614351203 i \approx -0.14288359 + 0.53924961 i\end{aligned}

Solutions were approximated using numerical methods.

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