$2x^{2}$ +6x+12>8(x+3)

asked by guest
on Nov 18, 2024 at 3:40 pm



You asked:

Solve the inequality \( 2 \cdot {x}^{2} + 6 x + 12 > 8 \cdot \left(x + 3\right) \) for the variable \(x\).

MathBot Answer:

\[x < -2 \wedge x > 3\]

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