Math Problem Solver

\[ \frac{6}{6} - \frac{2}{3} = \frac{1}{3} = 0.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{6}\) and \(\frac{-2}{3}\) is \(6\). \[ \begin{aligned} \frac{6}{6} - \frac{2}{3} &= \frac{6 \cdot 1}{6 \cdot 1} + \frac{-2 \cdot 2}{3 \cdot 2} \\ &= \frac{6 + -4}{6} \\ &= \frac{2}{6} \\&= \frac{1}{3} \end{aligned} \]