(125/100)x * 3(3/5)(x-16)
asked by guest on Jan 28, 2025 at 2:24 pm
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MathBot Answer:
125100x⋅3⋅35(x−16)=9x(x−16)4\displaystyle \frac{125}{100} x \cdot 3 \cdot \frac{3}{5} \left(x - 16\right) = \frac{9 x \left(x - 16\right)}{4} 100125x⋅3⋅53(x−16)=49x(x−16)
125100x⋅3⋅35(x−16)=9x24−36x\frac{125}{100} x \cdot 3 \cdot \frac{3}{5} \left(x - 16\right) = \frac{9 x^{2}}{4} - 36 x100125x⋅3⋅53(x−16)=49x2−36x