1 Find the equation of the tangent to:y = x - 2x ^ 2 + 3 at 2y = sqrt(x) + 1 at x = 4y = x ^ 3 - 5x at x = 1y = x - 2x ^ 2 + 3 at 2y = sqrt(x) + 1 at x = 4y = x ^ 3 - 5x at x = 1

asked by guest
on Nov 18, 2024 at 8:39 pm



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.