log⁡y=log⁡k+n log⁡x

solve for x

asked by guest
on Mar 24, 2025 at 1:07 am



You asked:

Solve the equation log⁡(y)=log⁡(k)+nlog⁡(x)\log\left( y \right) = \log\left( k \right) + n \log\left( x \right) for the unknown xx.

MathBot Answer:

x=e−log⁡(k)−log⁡(y)n\begin{aligned}x &= e^{- \frac{\log{\left(k \right)} - \log{\left(y \right)}}{n}}\end{aligned}

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