12, 19, 26, 33 ...
Find the 6th term of the following series.
You asked:
Determine the \(6^{\text{th}}\) term in the sequence \(12, 19, 26, 33, \ldots\).
MathBot Answer:
$$12,19,26,33,...$$The 6th term in this arithmetic sequence is $47$.
The nth term in this sequence is given by the formula:
Explicit Formula: $$a_n=7 n + 5$$
Recursive Formula: $$a_n=a_{n-1} + 7, \text{where } a_{1}=12$$
$$\begin{matrix}12&&19&&26&&33\\[6pt]&+7&&+7&&+7\\[6pt]\end{matrix}$$
Explicit Formula
The formula for an arithmetic sequence where $a_1$ is the 1st term, $d$ is the common difference, and $n$ is the term number is $$a_n=a_1 + d (n - 1)$$
Find $a_1$ and $d$: $$\begin{aligned} a_1&=12 \\ d&=7 \end{aligned}$$
The nth term rule is:$$\begin{aligned} a_n&=a_1 + d (n - 1) \\ &=12 + 7 (n - 1) \\ &=7 n + 5 \end{aligned}$$
Recursive Formula
The formula for an arithmetic sequence where $a_{n-1}$ is the (n-1)th term, $d$ is the common difference, and $n>1$ is $$a_n=a_{n-1} + d$$
Find $d$: $$\begin{aligned} d=7 \end{aligned}$$
The nth term rule is:$$\begin{aligned} a_n&=a_{n-1} + d \\ &=a_{n-1} + 7 \\ &=a_{n-1} + 7 \end{aligned}$$