10<2/3(9+12b)

asked by guest
on Oct 21, 2024 at 2:21 am



You asked:

Solve the inequality \( 10 < \frac{2}{3 \cdot \left(9 + 12 b\right)} \) for the variable \(b\).

MathBot Answer:

\[- \frac{3}{4} < b < - \frac{67}{90}\]

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