(3+2i)-(5-3i)+(-i)
asked by guest on Mar 28, 2025 at 10:04 pm
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MathBot Answer:
3+2i−(5−3i)+−i=−2+4i\displaystyle 3 + 2 i - \left(5 - 3 i\right) + -i = -2 + 4 i 3+2i−(5−3i)+−i=−2+4i
3+2i−(5−3i)+−i=−2+4i3 + 2 i - \left(5 - 3 i\right) + -i = -2 + 4 i3+2i−(5−3i)+−i=−2+4i
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.