8+$\frac{1}{3}$+9
You asked:
Evaluate the expression: \(8 + \frac{1}{3} + 9\)
MathBot Answer:
\[ 8 + \frac{1}{3} + 9 = \frac{52}{3} = 17.\overline{3} \]
The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{8}{1}\), \(\frac{1}{3}\), and \(\frac{9}{1}\) is \(3\). \[ \begin{aligned} 8 + \frac{1}{3} + 9 &= \frac{8 \cdot 3}{1 \cdot 3} + \frac{1 \cdot 1}{3 \cdot 1} + \frac{9 \cdot 3}{1 \cdot 3} \\ &= \frac{24 + 1 + 27}{3} \\ &= \frac{52}{3} \end{aligned} \]