8costcos2t
asked by guest on Jan 29, 2025 at 2:01 am
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MathBot Answer:
8cos(t)cos(2t)=8cos(2t)cos(t)8 \cos\left( t \right) \cos\left( 2 t \right) = 8 \cos{\left(2 t \right)} \cos{\left(t \right)}8cos(t)cos(2t)=8cos(2t)cos(t)