x=[1/(1-2.257)][ln (0.236/0.0783)+ 2.257ln((1-0.236)/(1-0.0783))]

asked by guest
on Mar 31, 2025 at 1:52 pm



You asked:

Solve the equation x=11−2.257(ln⁡(0.2360.0783)+2.257ln⁡(1−0.2361−0.0783))x = \frac{1}{1 - 2.257} \left(\ln\left( \frac{0.236}{0.0783} \right) + 2.257 \ln\left( \frac{1 - 0.236}{1 - 0.0783} \right)\right) for the variable xx.

MathBot Answer:

The solution is: x=−2257log⁡(76409217)1257−1000log⁡(2360783)1257≈−0.54077457x = - \frac{2257 \log{\left(\frac{7640}{9217} \right)}}{1257} - \frac{1000 \log{\left(\frac{2360}{783} \right)}}{1257} \approx -0.54077457

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