z = x-iy/x+iy then |z|

asked by guest
on Nov 27, 2024 at 7:46 am



MathBot Answer:

z=x+yiyix\left\lvert z\right\rvert = \left|{x + y i - \frac{y i}{x}}\right|


z=x+yiyix=x+yiiyx=yi+xiyx=yi+xiyx=x+yiyix\begin{aligned}\left|{z}\right|&=\left|{x + y i - \frac{y i}{x}}\right|\\&=\left|{x + y i - \frac{i y}{x}}\right|\\&=\left|{y i + x -\frac{i y}{x}}\right|\\&=\left|{y i + x - \frac{i y}{x}}\right|\\&=\left|{x + y i - \frac{y i}{x}}\right|\end{aligned}


ii is the imaginary unit, defined as i2=1i^2 = -1.