\int \frac{2x}{\:1+\sqrt{x}}dx
You asked:
Evaluate the integral: \(\int{\frac{2 x}{1 + \sqrt{x}}}dx\)
MathBot Answer:
Antiderivative
\[\int{\frac{2 x}{1 + \sqrt{x}}}dx = - 4 \log{\left(1 + \sqrt{x} \right)} - 2 x + 4 \sqrt{x} + \frac{4 x^{\frac{3}{2}}}{3} + C\]