d^2y/dx^2 − 9⋅(dy/dx)+18⋅y=0

asked by guest
on Apr 04, 2025 at 6:59 am



You asked:

Investigate the equation: d2ydx2−9⋅dydx+18y=0\frac{{d}^{2} y}{d {x}^{2}} - 9 \cdot \frac{d y}{d x} + 18 y = 0.

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