(x^(2)y^(-2))/(xy^(-2))*(y^(2))^(-2)=

asked by guest
on Mar 27, 2025 at 5:52 pm



You asked:

Evaluate the expression: x2y2xy2y22\frac{{x}^{2} {y}^{-2}}{x {y}^{-2}} {{y}^{2}}^{-2}

MathBot Answer:

x2y2xy2y22=xy4\frac{{x}^{2} {y}^{-2}}{x {y}^{-2}} {{y}^{2}}^{-2} = \frac{x}{y^{4}}