1496832÷7499

1525194÷6433

1520067÷4927

2411063÷0836

1512812÷4663

1543539÷0485

asked by guest
on Jan 12, 2025 at 5:54 am



MathBot Answer:

Original numbers in ascending order: \(\frac{1496832}{7499}\), \(\frac{1525194}{6433}\), \(\frac{1520067}{4927}\), \(\frac{1512812}{4663}\), \(\frac{2411063}{0836}\), \(\frac{1543539}{0485}\)
Sum: \( \frac{3206877878956593854145873}{449379129648827197820} \approx 7136.2412 \)
Mean: \( \frac{1068959292985531284715291}{898758259297654395640} \approx 1189.3735 \)
Sample standard deviation: \( \frac{\sqrt{1656763314250146827729595203262353550780887006422}}{898758259297654395640} \approx 1432.1462 \)
Median: \( \frac{14541697145}{45949202} \approx 316.4733 \)
Mode: No mode

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