Math Problem Solver

\[ 4 + 1\frac{3}{7} = \frac{38}{7} = 5.\overline{428571} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{4}{1}\), \(\frac{1}{1}\), and \(\frac{3}{7}\) is \(7\). \[ \begin{aligned} 4 + 1\frac{3}{7} &= \frac{4 \cdot 7}{1 \cdot 7} + \frac{1 \cdot 7}{1 \cdot 7} + \frac{3 \cdot 1}{7 \cdot 1} \\ &= \frac{28 + 7 + 3}{7} \\ &= \frac{38}{7} \end{aligned} \]