(3/x+2)-(2/x-1)
asked by guest on Feb 01, 2025 at 4:44 am
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3x+2−(2x−1)=3+1x\displaystyle \frac{3}{x} + 2 - \left(\frac{2}{x} - 1\right) = 3 + \frac{1}{x} x3+2−(x2−1)=3+x1
3x+2−(2x−1)=3+1x\frac{3}{x} + 2 - \left(\frac{2}{x} - 1\right) = 3 + \frac{1}{x}x3+2−(x2−1)=3+x1
3x+2−(2x−1)=3x+1x\frac{3}{x} + 2 - \left(\frac{2}{x} - 1\right) = \frac{3 x + 1}{x}x3+2−(x2−1)=x3x+1