4m^2+n^2+4mn

asked by guest
on Nov 20, 2024 at 6:39 am



You asked:

Evaluate the expression: \(4 \cdot {m}^{2} + {n}^{2} + 4 m n\)

MathBot Answer:

Evaluated



\(\displaystyle 4 \cdot {m}^{2} + {n}^{2} + 4 m n = 4 m^{2} + 4 m n + n^{2} \)


Factored

\[4 \cdot {m}^{2} + {n}^{2} + 4 m n = \left(2 m + n\right)^{2}\]