given that a = 7 y = -4 z = -2
evaluate $\frac{3x^2-2y}{3z^3}$
You asked:
Given the following equations: \[\begin{aligned}a &= 7\\ y &= -4\\ z &= -2\end{aligned}\] Evaluate \(\frac{3 \cdot {x}^{2} - 2 y}{3 \cdot {z}^{3}}\).
MathBot Answer:
\[\frac{3 \cdot {x}^{2} - 2 y}{3 \cdot {z}^{3}} = \frac{3 \cdot {x}^{2} - 2 \cdot -4}{3 \cdot {\left( -2 \right)}^{3}} = - \frac{x^{2}}{8} - \frac{1}{3}\]