200z=(x2x^{2}x2/2)+(y2y^{2}y2/24)
20z=x
4z=y/12
asked by guest on Nov 24, 2024 at 9:05 pm
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MathBot Answer:
The system of equations has 222 solutions.
x=0,y=0,z=0x = 0, y = 0, z = 0x=0,y=0,z=0x=50037,y=120037,z=2537x = \frac{500}{37}, y = \frac{1200}{37}, z = \frac{25}{37}x=37500,y=371200,z=3725