200z=($x^{2}$/2)+($y^{2}$/24)

20z=x

4z=y/12

asked by guest
on Nov 24, 2024 at 9:05 pm



You asked:

Solve the system of equations:\[\begin{aligned}200 z &= \frac{{x}^{2}}{2} + \frac{{y}^{2}}{24}\\20 z &= x\\4 z &= \frac{y}{12}\end{aligned}\]

MathBot Answer:

The system of equations has \(2\) solutions.

\[x = 0, y = 0, z = 0\]\[x = \frac{500}{37}, y = \frac{1200}{37}, z = \frac{25}{37}\]

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